Number of Equivalent Domino Pairs
Input: dominoes = [[1,2],[2,1],[3,4],[5,6]]
Output: 1def numEquivDominoPairs(self, dominoes: List[List[int]]) -> int:
mp = {}
count = 0
for i in range(0, len(dominoes)):
add = dominoes[i][0] + dominoes[i][1]
sub = abs(dominoes[i][0] - dominoes[i][1])
s = str(add) + "," + str(sub)
if (s in mp):
count = count + 1 + mp[s]
mp[s] += 1
else:
mp[s] = 0
return countLast updated