509. Fibonacci Number
π© Easy
F(0) = 0, F(1) = 1
F(N) = F(N - 1) + F(N - 2), for N > 1.Dynamic Programming
Complexity
Code
def fib(self, N: int) -> int:
store = [0] * (N+1)
for i in range(1, N+1):
if i < 3:
f = 1
else:
f = store[i-1] + store[i-2]
store[i] = f
return store[N]Last updated